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Here's a solution for Range Sum Query using Segment Tree:
Approach:
• Build a binary tree where each node stores sum of its range
• Leaf nodes represent individual array elements
• Internal nodes store sum of their children's ranges
Time: O(log n) query/update | Space: O(n)
class SegmentTree:
def __init__(self, arr):
self.n = len(arr)
self.tree = [0] * (4 * self.n)
self.build(arr, 1, 0, self.n - 1)
def build(self, arr, node, start, end):
if start == end:
self.tree[node] = arr[start]
else:
mid = (start + end) // 2
self.build(arr, 2*node, start, mid)
self.build(arr, 2*node+1, mid+1, end)
self.tree[node] = self.tree[2*node] + self.tree[2*node+1]Real people, real results, real testimonials.
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